(2d-2)/4*(4d+2)/(d^2-2d+1)

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Solution for (2d-2)/4*(4d+2)/(d^2-2d+1) equation: 


D( d )

d^2-(2*d)+1 = 0

d^2-(2*d)+1 = 0

d^2-(2*d)+1 = 0

d^2-2*d+1 = 0

d^2-2*d+1 = 0

DELTA = (-2)^2-(1*1*4)

DELTA = 0

d = 2/(1*2)

d = 1 or d = 1

d in (-oo:1) U (1:+oo)

(((2*d-2)/4)*(4*d+2))/(d^2-(2*d)+1) = 0

(((2*d-2)/4)*(4*d+2))/(d^2-2*d+1) = 0

((2*d-2)*(4*d+2))/(4*(d^2-2*d+1)) = 0

d^2-2*d+1 = 0

d^2-2*d+1 = 0

DELTA = (-2)^2-(1*1*4)

DELTA = 0

d = 2/(1*2)

d = 1 or d = 1

(d-1)^2 = 0

((2*d-2)*(4*d+2))/(4*(d-1)^2) = 0

( 2*d-2 )

2*d-2 = 0 // + 2

2*d = 2 // : 2

d = 2/2

d = 1

( 4*d+2 )

4*d+2 = 0 // - 2

4*d = -2 // : 4

d = -2/4

d = -1/2

d in { 1} 

d = -1/2

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